Question

Find the non-extraneous solution for 1 + √(x+2) = 6.

A) x = 15
B) x = 1
C) x = 20
D) x = 16

Answer 1

To find the non-extraneous solution for the equation 1 + √(x+2) = 6, you can subtract 1 from both sides, square both sides, and then solve for x.

Step-by-step explanation:

To find the non-extraneous solution for the equation 1 + √(x+2) = 6, we can start by subtracting 1 from both sides to isolate the square root term: √(x+2) = 5.

Next, we can square both sides of the equation to eliminate the square root: (x+2) = 5^2 = 25.

Finally, we solve for x by subtracting 2 from both sides: x = 25 - 2 = 23.

Therefore, the non-extraneous solution for the given equation is x = 23.