Final answer:
The temperature of the water will increase by approximately 10.32 degrees Celsius when 1036.0 J of heat are added to 24 g of water.
Step-by-step explanation:
To determine the change in temperature when 1036.0 J of heat are added to 24 g of water, we can use the formula Q = mcΔT, where Q is the heat added, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. The specific heat capacity of water is widely known to be 4.184 J/g°C.
So, using the formula:
ΔT = Q / (mc) = 1036.0 J / (24 g × 4.184 J/g°C) = 1036.0 J / 100.416 J/°C ≈ 10.32°C.
Therefore, the temperature of the water will increase by approximately 10.32 degrees Celsius.