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Resolver portavor te lo agradezco

Resolver portavor te lo agradezco-example-1
User Viraf
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1 Answer

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The system of equations y = -6x + 8 and y = 5x - 14 is solved by setting the two equations equal to each other to find x = 2 and then substituting back to find y = -4.

To solve the system of linear equations presented, namely y = -6x + 8 and y = 5x - 14, we set the two expressions for y equal to each other:

-6x + 8 = 5x - 14

Now, we combine like terms:

-6x - 5x = -14 - 8

-11x = -22

Divide both sides by -11 to solve for x:

x = 2

Substitute x back into either of the original equations to find y. Using the first equation:

y = -6(2) + 8

y = -12 + 8

y = -4

The solution to the system is x = 2 and y = -4.

The probable question may be:

Solve each system of equation

y=-6x+8

y=5x-14

User Andy Mardell
by
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