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The admission fee at an amusement park is $2.00 for children and $4.80 for adults. On a certain day, 252 people entered the park, and the admission fees collected totaled $896. How many children and how many adults were admitted?

A. 168 children and 84 adults
B. 112 children and 140 adults
C. 120 children and 132 adults
D. 140 children and 112 adults

User Roshit
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1 Answer

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Final answer:

To solve this problem, set up a system of equations. There were 112 children and 140 adults admitted.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's say 'c' represents the number of children and 'a' represents the number of adults admitted.

The total number of people admitted is 252, so we can write the equation:

c + a = 252

The total admission fees collected is $896, so we can write the second equation:

2c + 4.80a = 896

Now, we can solve this system of equations. We can multiply the first equation by 2 to eliminate 'c':

2c + 2a = 504

By subtracting this equation from the second equation, we get:

2.80a = 392

Dividing both sides by 2.80 gives us:

a = 140

Substituting this value back into the first equation, we can find 'c':

c + 140 = 252

c = 112

Therefore, there were 112 children and 140 adults admitted.

User Alexi Akl
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