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Study the reaction. 2HCl (g)+I2 (s)⇌2HI (g)+Cl₂ (g) When the reaction is at equilibrium, some amount of HI is added. The system then reaches equilibrium again. How does the concentration of Cl2 change compared to the first equilibrium?

A. The concentration is zero.
B. The concentration is higher.
C. The concentration is lower.
D. The concentration is the same

1 Answer

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Final answer:

d. The concentration of Cl2 will remain the same compared to the first equilibrium.

Step-by-step explanation:

d. When the reaction is at equilibrium, the concentration of Cl2 will remain the same compared to the first equilibrium. In a reversible reaction, such as the one shown, both the forward and reverse reactions are occurring simultaneously.

When some amount of HI is added and the system reaches equilibrium again, the concentration of HI will increase, but the concentration of Cl2 will remain unchanged because it is not directly involved in the reaction. Therefore, the answer is option D. The concentration of Cl2 is the same.

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