Final answer:
The deceleration of a plane that goes from 80 m/s to a complete stop in 10 seconds is -8 m/s².
Step-by-step explanation:
The question asks us to find the deceleration of a plane as it comes to a stop after landing. The plane has an initial velocity of 80 m/s and comes to rest in 10 seconds. To find the deceleration, we use the formula for acceleration (a), which is change in velocity (Δv) over time (t): a = Δv / t.
The change in velocity is the final velocity (0 m/s) minus the initial velocity (80 m/s), giving us -80 m/s. When we divide this by the time (10 s), we get a deceleration of -8 m/s², making the correct answer D. -8 m/s².
To find the deceleration of the plane, we can use the formula acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity of the plane is 80 m/s, the final velocity is 0 m/s (since the plane comes to rest), and the time taken is 10 seconds. Substituting these values into the formula, we get acceleration = (0 - 80) / 10 = -8 m/s². Therefore, the correct answer is D. -8 m/s².