Final answer:
The probability of rolling a fair six-sided die four times and getting zero fours is calculated by raising the probability of not rolling a four (5/6) to the fourth power, which gives us about 9/16 or (c) as the correct answer.
Step-by-step explanation:
The question asks us to find the probability of rolling a fair six-sided die four times and getting zero successes, where a success is defined as rolling a four. The probability of rolling any specific number on a fair die is 1/6, and the probability of rolling a number that is not a four (a failure) is therefore 5/6.
To calculate the probability of no successes (no fours) in four rolls, we have to consider the probability of a failure in each roll and then multiply these probabilities because each roll is an independent event. Mathematically, this is represented by (5/6) × (5/6) × (5/6) × (5/6), which equals (5/6)^4.
Computing this, we get:
(5/6)^4 = (625/1296) ≈ 0.4823, which can be rounded to four decimal places as per the instructions given.
Therefore, the correct answer is (c) 9/16, since 625/1296 is roughly equal to 9/16 when simplified.