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What gametes are produced by genotype AaBb if genes are on different chromosomes, assuming no crossing over?

A. AB, ab
B. Ab, aB
C. AB, aB
D. Ab, ab

User Asherlc
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1 Answer

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Final answer:

The genotype AaBb produces four types of gametes: AB, Ab, aB, and ab, according to the Law of Independent Assortment, because the genes are on different chromosomes and there is no crossing over.

Step-by-step explanation:

Types of Gametes Produced by Genotype AaBb

The question asks what types of gametes are produced by the genotype AaBb when genes are on different chromosomes, assuming no crossing over. An individual with the genotype AaBb has two heterozygous gene pairs, which are located on different chromosomes. The Law of Independent Assortment states that alleles for separate traits are passed independently of one another from parents to offspring. Thus, each pair of alleles segregates independently during the formation of gametes by meiosis.

Because there is no crossing over and the genes reside on different chromosomes, this results in four possible combinations of gametes: AB, Ab, aB, and ab. Therefore, the correct answer to the question is c. AB, Ab, aB, ab.

User NatFar
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