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An ideal gas in a 50.0 L tank has a

pressure of 2.45 atm at 22.5°C.
How many moles of gas are in
the tank?

1 Answer

10 votes

Answer:

5.05225 moles

Step-by-step explanation:

The computation of the number of moles of gas in the tank is shown below:

Given that

Volume = V = 50 L = 50.0 × 10^-3m^3

Pressure = P = 2.45 atm = 2.45 × 101325

Temperature = T = 22.5°C = (22.5 + 273)k = 295.5 K

As we know thta the value of gas constant R is 8.314 J/mol.K

Now

PV = nRT

n = PV ÷ RT

= ((2.45 × 101325) (50.0 × 10^-3)) ÷ ((8.314) (295.5))

= 5.05225 moles

User GaelF
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