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A restaurant is offering chicken specials numbered 1,2,3, beef specials numbered 1,2,3,4, and vegetarian specials numbered 1,2. If a single special is picked at random, what is the probability that the selected special is NOT vegetarian?

a) 5/6
b) 1/3
c) 2/3
d) 1/2



User Samual
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1 Answer

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Final answer:

To find the probability that the selected special is NOT vegetarian, we need to calculate the ratio of the number of non-vegetarian specials to the total number of specials. The probability that the selected special is NOT vegetarian is 7/9.

Step-by-step explanation:

The restaurant offers chicken specials numbered 1,2,3; beef specials numbered 1,2,3,4; and vegetarian specials numbered 1,2. To find the probability that the selected special is NOT vegetarian, we need to calculate the ratio of the number of non-vegetarian specials to the total number of specials.

The number of non-vegetarian specials (chicken and beef) is 3 + 4 = 7.

The total number of specials is 3 (chicken specials) + 4 (beef specials) + 2 (vegetarian specials) = 9.

Therefore, the probability that the selected special is NOT vegetarian is 7/9.

User Teymur Mardali
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