Question

Please answer for this in class 12 physics​

Answer 1

w1:w2 = 16:1

Step-by-step explanation:

As we know that ration of amplitude is equal to

`(a_1)/(a_2) = \sqrt{(w_1)/(w_2) }`

here w1 and w2 are the widths of the slit.

`(I _(min))/(I_(max)) = ((a_1-a_2)^2)/((a_1+a_2)^2) \\(9)/(25) = ((1-(a_2)/(a_1) )^2)/((1+(a_2)/(a_1) )^2) \\(3)/(5) = ((1-(a_2)/(a_1) ))/((1+(a_2)/(a_1) ))\\8 (a_2)/(a_1) = 2\\(a_1)/(a_2) = 4`

Again

`(a_1)/(a_2) = \sqrt{(w_1)/(w_2) }`

`4 = \sqrt{(w_1)/(w_2) }\\(w_1)/(w_2) = 16`

w1:w2 = 16:1