Final answer:
The weight of water displaced by the body is 0.98 N.
Step-by-step explanation:
To find the weight of water displaced by the body, we need to first calculate the volume of the half of the body that is submerged in water. Since the volume of the whole body is given as 200 cm^3, the volume of the submerged half will be half of that, which is 100 cm^3.
Next, we need to convert the volume from cm^3 to m^3, as the density of water is usually given in kg/m^3. Since 1 cm^3 is equal to 1x10^-6 m^3, the volume of the submerged half is 100x10^-6 m^3.
The weight of water displaced can be calculated using the formula W = V x ρ x g, where W is the weight, V is the volume, ρ is the density of water, and g is the acceleration due to gravity (approximately 9.8 m/s^2). Substituting the values, we get W = (100x10^-6) x 1000 kg/m^3 x 9.8 m/s^2 = 0.98 N.