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For the functions (f(x) = -10x + 15) and (g(x) = 3x + 9), find the following.

1. ((f ∘ g)(x)) and its domain
2. ((g ∘ f)(x)) and its domain

a. ((f ∘ g)(x) = -30x + 24), The domain is (ℝ)
b. ((g ∘ f)(x) = -30x + 24), The domain is (ℝ)
c. ((f ∘ g)(x) = 30x - 24), The domain is (ℝ)
d. ((g ∘ f)(x) = 30x - 24), The domain is (ℝ)

User Carlos H
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Final answer:

Composition of the given functions results in (f \circ g)(x) = -30x - 75, and (g \circ f)(x) = -30x + 54. Both compositions have a domain of all real numbers (ℝ). Thus, options a and b provided in the question are incorrect.

Step-by-step explanation:

To find the composition of functions (f \circ g)(x) and (g \circ f)(x), we simply substitute the inside function into the outside function and simplify. For the functions given, f(x) = -10x + 15 and g(x) = 3x + 9, let's perform the substitutions.

(f \circ g)(x) means plugging g(x) into f(x). So:

f(g(x)) = f(3x + 9) = -10(3x + 9) + 15 = -30x - 90 + 15 = -30x - 75.

Therefore, option a is incorrect.

For (g \circ f)(x), we plug f(x) into g(x):

g(f(x)) = g(-10x + 15) = 3(-10x + 15) + 9 = -30x + 45 + 9 = -30x + 54.

Therefore, option b is incorrect.

The domain for both composite functions is \(\mathbb{R}\), the set of all real numbers, because there are no restrictions such as division by zero or square roots of negative numbers in either composed function.

User DWR
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