Answer:
The circular field would require 1232 kg of fertilizer.
Explanation:
0.5
takes 1 kg of fertilizer.
For a circular field of radius 14 m, its area = area of a circle
area of a circle =


So that,
Area of the circular field =
x 14 x 14
= 22 x 2 x 14
= 616
Area of the field = 616

Since, 0.5
takes 1 kg of fertilizer. Let the kilograms of fertilizer required by the field be represented by x.
Thus,
x =

= 1232
x = 1232 kg
Therefore, the circular field would require 1232 kg of fertilizer.