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Two springs of stiffness 0.04 N/M and 1.6 N/M each carrying a load of 4.0 kg are set into horizontal oscillation. Determine the ratio of their period of oscillation.

a. 1:1
b. 2:1
c. 1:2
d. 4:1

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Final answer:

To find the ratio of their period of oscillation, use the formula T = 2π√(m/k) for each spring and calculate the ratio T1/T2 by simplifying the respective time periods.

Step-by-step explanation:

The question involves determining the ratio of periods of oscillation for two springs with different stiffness values, each carrying a load. The oscillation period (T) for a spring-mass system in simple harmonic motion is given by the formula T = 2π√(m/k), where m is the mass of the load and k is the spring constant or stiffness.

For the first spring with a stiffness of 0.04 N/m:

T1 = 2π√(4.0 kg / 0.04 N/m)

For the second spring with a stiffness of 1.6 N/m:

T2 = 2π√(4.0 kg / 1.6 N/m)

The ratio of their periods T1/T2 can be calculated by dividing the formulas, simplifying, and comparing the results to the given options.

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