Question

How many atoms are in 3.5 moles of Phosphorus

Answer 1

There are approximately
`\(2.107 * 10^(24)\)` phosphorus atoms in 3.5 moles of phosphorus.

To determine the number of atoms in 3.5 moles of phosphorus, you can use Avogadro's number, which states that one mole of any substance contains approximately
`\(6.022 * 10^(23)\)` entities (atoms, molecules, ions, etc.). In this case, 3.5 moles of phosphorus would be:

`\[3.5 \text{ moles} * 6.022 * 10^(23) \text{ atoms/mole} \approx 2.107 * 10^(24) \text{ atoms}.\]`

Therefore, there are approximately
`\(2.107 * 10^(24)\)` phosphorus atoms in 3.5 moles of phosphorus. This calculation is based on the concept that each mole of phosphorus contains Avogadro's number of atoms.

This large number emphasizes the vast scale of atomic quantities, reflecting the microscopic nature of matter and the need for the mole as a bridge between macroscopic and atomic scales in chemistry.