Final answer:
To calculate the number of moles of nitric acid that can be prepared, we can use the ideal gas law equation PV = nRT. By rearranging the equation, we can solve for n, the number of moles. Substituting the given values into the equation, we find that 75.7 moles of nitric acid can be prepared using 450. L of NO2 at 5.00 atm and 295 K.
Step-by-step explanation:
In this question, we are given the following equation for the synthesis of nitric acid:
3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)
We are asked to determine how many moles of nitric acid can be prepared using 450. L of NO2 at 5.00 atm and 295 K.
To solve this problem, we need to use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Given:
P = 5.00 atm
V = 450. L
T = 295 K
We can rearrange the ideal gas law to solve for n:
n = PV / RT
Substituting the given values:
n = (5.00 atm) * (450. L) / (0.0821 L*atm/mol*K * 295 K)
= 75.7 mol
Therefore, 75.7 moles of nitric acid can be prepared using 450. L of NO2 at 5.00 atm and 295 K.