Question

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.45 T.

What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.1 × 10^7 m/s?
a) 29.05 V
b) 145.25 V
c) 72.63 V
d) 14.52 V

Answer 1

The potential difference required to accelerate electrons to a speed of 6.1 x 10^7 m/s is approximately 29.05 V.

Step-by-step explanation:

To determine the potential difference required to accelerate electrons to a speed of 6.1 x 107 m/s, we can use the equation:

V = (1/2)mv2/q

where V is the potential difference, m is the mass of the electron, v is the final velocity of the electron, and q is the charge of the electron.

Substituting the given values, we have:

V = (1/2)(9.11 x 10-31 kg)(6.1 x 107 m/s)2/(-1.60 x 10-19 C)

Simplifying the equation, the potential difference is approximately 29.05 V.