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Perimeter/area (triangles)

Perimeter/area (triangles)-example-1

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Answer:

12 ft²

50 ft²

Explanation:

∆ABD = ∆CBD

Perimeter of ∆ABD = 12 ft²

Perimeter of triangle ∆CBD

If ∆ABD = ∆CBD

Then, Perimeter of ∆CBD = 12 ft²

∆ABC = ∆CDA

Area of ∆ABC = 25 ft²

Then the area of rectangle ABCD = Area of ∆ABC + Area of ∆CDA

= 25 ft² + 25 ft²

= 50 ft²

User Sandeep Dhiman
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