Question

A dealer bought a number of horses at $344.00 each, and a number of bullocks at $265.00 each. He then discovered that the horses had cost him in all $33.00 more than the bullocks. Now, what is the smallest number of each that must have bought?

a. 4 horses and 3 bullocks
b. 3 horses and 4 bullocks
c. 5 horses and 2 bullocks
d. 2 horses and 5 bullocks

Answer 1

The smallest number of horses and bullocks that must have been bought is 3 horses and 4 bullocks.

Step-by-step explanation:

To find the smallest number of horses and bullocks that must have been bought, we need to set up equations based on the given information. Let's assume the number of horses is 'h' and the number of bullocks is 'b'.

The cost of the horses is given by 344h and the cost of the bullocks is given by 265b. We are also told that the cost of the horses is $33 more than the cost of the bullocks. Therefore, we can set up the equation:

344h = 265b + 33

We are looking for the smallest values of h and b that satisfy this equation. By trying out the answer choices, we find that the correct answer is 3 horses and 4 bullocks (choice b), as it satisfies the equation.