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Find the area of the shape using Pythagoras Theorem please​

Find the area of the shape using Pythagoras Theorem please​-example-1
User Samuel Tan
by
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1 Answer

8 votes

Answer:

122.09 (the answer may change depending on how many decimals you need if you need more or less just follow the steps using however many decimals)

Explanation:

to get the other triangle side do 18-11= 7

then use the Pythagoras theorem to solve for the other side so 7^2+b^2=11^2

49+b^2= 121

121-49= b^2

72=b^2

b= 8.48(simplified)

then use that side to get the area of the rectangle:

8.42×11=92.62

then get area of the triangle:

1/2(8.42×7)=29.47

add the 2 areas to get total area:

92.62+29.47=122.09

User Singletony
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