Final answer:
The correct model is 2300(\(\frac{2}{3}\))^n, and after 5 days, the tortoise would have 302.9 feet remaining to reach the ocean.
Step-by-step explanation:
The correct model to predict the distance that the tortoise must travel to the ocean after traveling each day one-third of the remaining distance is 2300(\(\frac{2}{3}\))^n, where n is the number of days traveled. Each day the tortoise covers one-third of the distance to the ocean, which leaves two-thirds of the distance for the next day.
After 5 days, using the model 2300(\(\frac{2}{3}\))^5, the computation is as follows:
- 2300 * (\(\frac{2}{3}\))^1 = 1533.3 (after 1 day)
- 1533.3 * (\(\frac{2}{3}\))^1 = 1022.2 (after 2 days)
- 1022.2 * (\(\frac{2}{3}\))^1 = 681.5 (after 3 days)
- 681.5 * (\(\frac{2}{3}\))^1 = 454.3 (after 4 days)
- 454.3 * (\(\frac{2}{3}\))^1 = 302.9 feet (rounded to the nearest tenth, after 5 days)
The remaining distance to the ocean after 5 days of travel is 302.9 feet.