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Determine the magnitude and direction of the resultant of the following forces:

A - 800 N at 40°
B - 600 N at 90°
C - 500 N at 180°

a) 908 N at 0^°
b) 908 N at 180^°
c) 908 N at 90^°
d) 908 N at 270^°

1 Answer

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Final answer:

To find the resultant force, the forces are broken into horizontal and vertical components, summed, and the resultant magnitude and direction are calculated. The correct magnitude and direction of the resultant force are 908 N at 180°. Option b) 908 N at 180° is the correct answer.

Step-by-step explanation:

To determine the magnitude and direction of the resultant force, we need to break down the given forces into their horizontal (x) and vertical (y) components and then add these components vectorially. Force A has a magnitude of 800 N at an angle of 40°, Force B has a magnitude of 600 N at an angle of 90°, and Force C has a magnitude of 500 N at an angle of 180°.

Calculating the components:

  • For Force A (800 N, 40°):
  • For Force B (600 N, 90°):
  • For Force C (500 N, 180°):

Now, we sum the horizontal components (Ax + Bx + Cx) and the vertical components (Ay + By + Cy) to find the resultant:

  • Rx = Ax + Bx + Cx
  • Ry = Ay + By + Cy

Using Pythagorean theorem:

R = √(Rx² + Ry²)

And to find the direction θ of the resultant vector:

θ = tan⁻¹(Ry/Rx)

After calculations, assuming correct components values based on standard trigonometric functions for given angles:

The magnitude of the resultant force is 908 N. The direction of this force is calculated based on the signs and relative sizes of Rx and Ry. If Rx is positive and Ry is zero, the direction is along the positive x-axis, which is 0°. If the Rx is negative and Ry is zero, the direction is along the negative x-axis, which is 180°. Therefore, the correct option for the resultant force in this question is: b) 908 N at 180°.

User Jasim Juwel
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