Question

Two parallel plates of area 100 cm² are given charges of equal magnitudes 8 µC but opposite signs. The electric field within the dielectric material filling the space between the plates is 14*10^3 V/m. Calculate the dielectric constant of the material.

a) 1
b) 2
c) 3
d) 4

Answer 1

The dielectric constant of the material is approximately 22.857.

Step-by-step explanation:

The dielectric constant of a material is the ratio of the electric field in vacuum to the net electric field in the material. In this case, the electric field within the dielectric material is given as 14*10^3 V/m. The dielectric constant, also known as the relative permittivity, can be calculated using the formula:

K = Evacuum / Ematerial

Substituting the values, we have:

K = 3.20 × 10^5 V/m / 14 × 10^3 V/m = 22.857

Therefore, the dielectric constant of the material is approximately 22.857.