Question

Find the value of expression - 17x-19xpwer4 - 21x power 2,when x=3

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Answer 1

`-17x - 19x^4 - 21x^2 = -1779` when
`x = 3`

Explanation:

Given

`-17x - 19x^4 - 21x^2`

`x = 3`

Required

Solve

Substitute 3 for x in
`-17x - 19x^4 - 21x^2`

`-17x - 19x^4 - 21x^2 = -17*3 - 19*3^4 - 21*3^2`

Evaluate all exponents

`-17x - 19x^4 - 21x^2 = -17*3 - 19*81 - 21*9`

`-17x - 19x^4 - 21x^2 = -51 - 1539- 189`

`-17x - 19x^4 - 21x^2 = -1779`