Question

PLZZZ HELPPP

1- A positive charge of 3x10-7 is located in a field of 27N/C directed toward the south. What is the force acting on the charge?



2- A positive test charge of 5x10-6Cis in an electric field that exerts a force of 2x10-4N on it. What is the magnitude of the electric field at the location of the test charge?

Answer 1

1) 8.1x
`10^(-6)` N

2) 4.0x
`10^(1)` N/C

Step-by-step explanation:

1) E = F/q ---> F = Eq = (27 N/C) x (3x
`10^(-7)`)

= 8.1x
`10^(-6)` N

2) E =
`(F)/(q)` =
`(2.0X10^(-4) )/(5.0X10^(-6) )`

= 4.0x
`10^(1)` N/C