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12x^2 -75=3(2x+?) (2x-5)

User Jmbucknall
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To solve the equation 12x^2 - 75 = 3(2x + ?)(2x - 5), you can find the factors of 4x^2 - 25 using the difference of squares formula.

Step-by-step explanation:

To solve the equation 12x^2 - 75 = 3(2x + ?)(2x - 5), we can start by dividing both sides of the equation by 3 to simplify it:

4x^2 - 25 = (2x + ?)(2x - 5)

We can then find the factors of 4x^2 - 25 by using the difference of squares formula:

(2x + ?)(2x - 5) = (2x + ?)(√(4x^2) - √25)

Applying the difference of squares formula, we get:

(2x + ?)(2x - 5) = (2x + ?)(2x - 5)

This equation cannot be further simplified, so we have found the factors of 4x^2 - 25.

The probable question can be: How to solve the given equation 12x^2 -75=3(2x+?) (2x-5)

User Tolga
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