Final answer:
To find the moles of NH₄F in 75.2 grams, calculate the molar mass of NH₄F and then divide the mass by the molar mass, resulting in approximately 1.318 moles.
Step-by-step explanation:
To calculate the number of moles in 75.2 grams of NH₄F, we first need to determine its molar mass. The molar mass of NH₄F, also known as ammonium fluoride, is the sum of the atomic masses of all the atoms in the formula. This is calculated as follows: N (14.01 g/mol) + H₄ (4 x 1.01 g/mol) + F (19.00 g/mol) = 57.05 g/mol. Now we use the formula:
Number of moles = mass (g) / molar mass (g/mol)
Number of moles of NH₄F = 75.2 g / 57.05 g/mol
After calculating this, we obtain approximately 1.318 moles of ammonium fluoride.