The measure of angle BAC is 18 degrees.
To solve for x in triangle ABC, we use the fact that the sum of the angles in a triangle is always 180 degrees.
Since angle ABC is given as 90 degrees and angle BCA is 4 times angle BAC (4x), we can set up the following equation:
angle BAC (x) + angle BCA (4x) + angle ABC (90) = 180
By combining like terms, we get:
x + 4x + 90 = 180
This simplifies to:
5x + 90 = 180
Subtract 90 from both sides:
5x = 90
Now, divide both sides by 5 to find the value of x:
x = 18
Therefore, the measure of angle BAC is 18 degrees.
The probable question may be:
In triangle ABC, angle ABC=90 , angle BAC=x and angle BCA=4x. How do I solve for X ?