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Calculate the concentration of the solution formed when 95 ml of water is added to 5 ml of 0.500M HCl. Show working out.

A) 0.025 M
B) 0.050 M
C) 0.100 M
D) 0.500 M

User Nhu
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1 Answer

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Final answer:

The concentration of the solution formed when 95 ml of water is added to 5 ml of 0.500M HCl is 0.025 M.

Step-by-step explanation:

To calculate the concentration of the solution formed when 95 ml of water is added to 5 ml of 0.500M HCl, you can use the formula:

C1V1 = C2V2

Where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume. In this case, C1 = 0.500M, V1 = 5 ml, V2 = 100 ml (because 95 ml of water is added to 5 ml of HCl), and we need to solve for C2. Plugging these values into the formula, we have:

(0.500M)(5 ml) = C2(100 ml)

C2 = (0.500M)(5 ml) / 100 ml = 0.025 M.

User BeOn
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