Question

How many moles of hydrochloric acid are needed to neutralize 2.4 mol of calcium hydroxide?

1) 1.2 mol
2) 2.4 mol
3) 3.6 mol
4) 4.8 mol

Answer 1

4) 4.8 mol

To neutralize 2.4 mol of calcium hydroxide, 4.8 mol of hydrochloric acid are needed because the stoichiometry of the reaction requires two moles of HCl for every mole of Ca(OH)2.

Step-by-step explanation:

To determine how many moles of hydrochloric acid (HCl) are needed to neutralize 2.4 mol of calcium hydroxide (Ca(OH)2), we look at the stoichiometry of the balanced chemical equation for the reaction between HCl and Ca(OH)2. The balanced equation is:

Ca(OH)2 + 2HCl → CaCl2 + 2H2O

This equation shows that one mole of Ca(OH)2 reacts with two moles of HCl. Therefore, to neutralize 2.4 mol of Ca(OH)2, we need:

2.4 mol Ca(OH)2 × (2 mol HCl / 1 mol Ca(OH)2) = 4.8 mol HCl

The correct answer is option 4) 4.8 mol.