Final answer:
To neutralize the given amount of phosphoric acid, 3. 3.0 mol of strontium hydroxide is needed.
Step-by-step explanation:
To determine the number of moles of strontium hydroxide needed to neutralize phosphoric acid, we first need to write a balanced chemical equation for the reaction:
3H3PO4 + 6Sr(OH)2 → 2Sr3(PO4)2 + 6H2O
From the balanced equation, we can see that 3. 3 moles of phosphoric acid react with 6 moles of strontium hydroxide. Therefore, the correct answer is 3.0 mol of strontium hydroxide.