question:-
The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.
Answer:-
- width = 1.88
- length = 91.88
let's find out
let X = width
X+90 = length
so,
- 2x + 2(x+90) = 340
- 2x + 2x + 180 = 340
- 4x + 180 = 340
- X = 340÷180
- X = 1.88
therefore X = 1.88
so,
- width = 1.88
- length = 1.88 + 90 = 91.88
________________________________________
related question with solution:
question:
The perimeter of a rectangular field is 360 yd. The length is 40 yd longer than the width. Find the dimensions.
AnsWer
Let x = width
x + 40 = length
2x + 2(x+40) = 360
4x + 80 = 360
4x = 280
x = 70
Width = x = 70 yd
Length = x + 40 = 110 yd
______________________________________