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You're asked to add 15 mEq of potassium chloride per 1,000 mL of Normosol. Potassium chloride is available as 20 mEq/10 mL. How much potassium chloride is needed for a 3 L bag of Normosol?

a) 60 mEq
b) 75 mEq
c) 90 mEq
d) 105 mEq

User Suzu
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1 Answer

2 votes

Final answer:

To calculate the required amount of potassium chloride for a 3 L bag of Normosol, multiply the requirement of 15 mEq / 1,000 mL by the volume of the bag, resulting in 45 mEq needed. However, this answer is not listed in the given options.

Step-by-step explanation:

To calculate how much potassium chloride is needed for a 3 L bag of Normosol, when the requirement is 15 mEq of potassium chloride per 1,000 mL, we will first determine the total amount needed for 3,000 mL (since 3 L = 3,000 mL). Therefore, we calculate:

  • 15 mEq/1,000 mL x 3,000 mL = 45 mEq of potassium chloride for 3 L of Normosol.

Given that potassium chloride is available as 20 mEq/10 mL, we find out how many milliequivalents there are in one milliliter:

  • 20 mEq in 10 mL implies 2 mEq in 1 mL.
  • Thus, to get 45 mEq, we need (45 mEq) / (2 mEq/mL) = 22.5 mL of the potassium chloride solution.

However, since options are given in mEq, we don't need to convert to mL. The correct answer for the amount of potassium chloride needed is 45 mEq, which is not in the provided options, suggesting a possible typo or incorrect options listed.

User Masood Khaari
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