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Logan had 2 tens, five ones, a 100 dollar bill, three quarters, two dimes, one nickel, and three pennies. How much did Logan have altogether?

a) $122.78
b) $128.88
c) $111.38
d) $120.53

User Pinkey
by
7.7k points

1 Answer

4 votes

Final answer:

After adding the value of the different denominations of currency and coins Logan had, the total is $125.03. This total is not listed among the answer choices provided by the student, indicating a possible error in the options or the question itself.

Step-by-step explanation:

Let's calculate the total amount of money that Logan had by adding up the value of each type of currency and coin he possessed:

  • 2 tens = 2 × $10 = $20
  • 5 ones = 5 × $1 = $5
  • 1 one hundred dollar bill = $100
  • 3 quarters = 3 × $0.25 = $0.75
  • 2 dimes = 2 × $0.10 = $0.20
  • 1 nickel = $0.05
  • 3 pennies = 3 × $0.01 = $0.03

Adding all of these values together:

$20 (tens) + $5 (ones) + $100 (one hundred dollar bill) + $0.75 (quarters) + $0.20 (dimes) + $0.05 (nickel) + $0.03 (pennies) = $125.03.

Therefore, the correct total is $125.03, which is not listed in the options provided by the student. Either there is an error in the options given, or the student made a mistake in their choices.

User Debran
by
8.4k points
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