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Two large parallel metal plates carrying equal and opposite electric charges are separated by a distance 38mm.The electric field between them is uniform with magnitude 760Nc-1A.What is the p.d between the sheetsB.What is the surface charge density of the +ve sheetC.what is the sheet at higher potential ​

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Final answer:

The potential difference (p.d) between two parallel plates carrying equal and opposite electric charges is calculated using the formula: p.d = electric field x separation distance. The surface charge density of the positive plate can be calculated using the formula: surface charge density = charge / area. The sheet at higher potential will be the positive plate.

Step-by-step explanation:

The potential difference (p.d) between two parallel plates carrying equal and opposite electric charges can be calculated using the formula:

p.d = electric field x separation distance

Given that the electric field is 760 N/C and the separation distance is 38 mm (convert to meters by dividing by 1000), we can calculate the p.d. Substitute these values into the formula to find the p.d between the plates.

To calculate the surface charge density of the positive plate, we can use the formula:

surface charge density = charge / area

Finally, the sheet at higher potential will be the positive plate since positive charges have higher potential compared to negative charges.

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