Question

Part B The three remaining sides of ABCD are not purely horizontal or vertical. You will use the Pythagorean Theorem to find the lengths of these sides. Start with AB place point E at (-5, 4), and draw AE and EB. Now you have right AAEB with AB as the hypotenuse. Find EB and AE using the coordinates of A, B, and E. Then use the Pythagorean Theorem to find AB. Show your work.​

Answer 1

AE = |4 + 4| = 8

EB = |1 + 5| = 6

Distance Formula: d = √(x2-x1)2 + (y2-y1)2

AB = √(x2-x1)2 + (y2-y1)2

A = (-5,-4)

B = (1,4)

AB = √(1-(-5))2 + (4-(-4))2

AB = √(6)2 + (8)2

AB = √(6)2 + (8)2

AB = √36 + 64

AB = √100

AB = 10

Answer 2

EB = |1 – (− 5)| = 6

AE = |4 – (− 4)| = 8

Using the Pythagorean Theorem to find AB:

AB2 = EB2 + AE2

AB2 = 62 + 82

AB2 = 36 + 64

AB =
`√(100)`

AB = 10

Explanation: