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on a car trip the time of the trip is inversely proportional to the speed traveled once the car drove 85 mph and it took them 63 minutes if a different car made the same trip at a speed 45 mph how many minutes would the trip take

User Okmich
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Final answer:

To find out how long it would take the second car to complete the trip at a slower speed, use the inverse proportion formula. For the first car at 85 mph, it took 63 minutes; for the second car at 45 mph, the trip would take 119 minutes.

Step-by-step explanation:

The question involves finding out how long it would take a different car to complete the same trip at a different speed, given that the original time and speed are known. We know that time and speed are inversely proportional for a constant distance: as speed increases, time decreases, and vice versa.

For the first car, the time taken was 63 minutes at a speed of 85 mph. We can use this information to set up a proportion for the second car, which is traveling at 45 mph. The formula that expresses this inverse proportion is time1 x speed1 = time2 x speed2. Plugging in known values:

63 minutes x 85 mph = time2 x 45 mph.

To solve for time2, divide both sides by 45 mph:

time2 = (63 minutes x 85 mph) / 45 mph.

Calculate the value of time2 to find the answer:

time2 = (5355 minutes x mph) / 45 mph.

time2 = 119 minutes.

Therefore, the second car would take 119 minutes to complete the same trip at a speed of 45 mph.

User Kenny Kurochkin
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