In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the percent yield?

asked Mar 19, 2023 70.6k views

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Percentage

$\\ \tt\hookrightarrow (16.12)/(70)* 100=23.02\%$

Yield percentage is 23.02%

Scully answered Mar 22, 2023

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Answer:

I don't know please very sorry for your birthday

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