Question

55. Given the equation N₂(g) + 3H2(g) → 2NH3(g), what is the total number of moles of NH3 produced when 10. mol of H₂ reacts completely with N₂?

Can you break down how to answer the question

Answer 1

When 10 moles of H₂ react completely with N₂ according to the equation N₂(g) + 3H₂(g) → 2NH₃(g), a total of 6.67 moles of NH₃ is produced, based on the stoichiometric ratio of 3 moles H₂ to 2 moles NH₃.

Step-by-step explanation:

Given the balanced chemical equation N₂(g) + 3H₂(g) → 2NH₃(g), when 10 moles of H₂ react completely, we can determine the number of moles of NH₃ produced by looking at the mole ratio provided by the coefficients in the balanced equation. According to the coefficients, 3 moles of hydrogen gas react with 1 mole of nitrogen gas to produce 2 moles of ammonia gas.

Using stoichiometry, we use the ratio of 3 moles of H₂ : 2 moles of NH₃ to calculate the amount of ammonia produced from 10 moles of H₂:

1. 
   
3. Set up a ratio using the coefficients from the balanced equation:
   (2 moles NH₃ / 3 moles H₂)
4. 
   
6. Multiply by the given number of moles of H₂:
   (2 moles NH₃ / 3 moles H₂) × 10 moles H₂
7. 
   
9. Calculate the result:
   20/3 = 6.67 moles NH₃

Therefore, the total number of moles of NH₃ produced when 10 moles of H₂ react completely is 6.67 moles of NH₃.