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Geometry problem above^^^ In the figure at the right FGH ~ KLJ....

Geometry problem above^^^ In the figure at the right FGH ~ KLJ....-example-1
User Abligh
by
4.9k points

1 Answer

7 votes

Answer:

x = 12

y = 4.5

Explanation:

Since ∆FGH ~ ∆KLJ, therefore, we would have the following proportion:


(FG)/(KL) = (GH)/(LJ) = (FH)/(KJ)


(9)/(y) = (x)/(6) = (6)/(3)

✔️Let's solve for x using:


(x)/(6) = (6)/(3)

Multiply both sides by 6


(x)/(6)*6 = (6)/(3)*6


x = (6*6)/(3)


x = 12

✔️Solve for y using:


(9)/(y) = (6)/(3)

Cross multiply


y*6 = 3*9

6y = 27

y = 27/6

y = 4.5

User Robert Rose
by
4.4k points