220k views
4 votes
In the presence of air drag, an object of mass m = 0.150 kg falls from height of 13.00 m to 6.70 m with the terminal speed vT. How much work did the drag force do on the object? Give your answer in Joules to two decimal places. Sign matters.

1 Answer

4 votes

Final answer:

The work done by the drag force on the object is 61.74 J (in Joules).

Step-by-step explanation:

The work done by the drag force on the object can be calculated using the formula: Work = Force x Distance. In this case, the force is the drag force and the distance is the difference in height through which the object falls.

The drag force can be calculated using the formula: Drag Force = (1/2) x density x velocity^2 x cross-sectional area x drag coefficient. However, since the terminal speed is reached, the drag force is equal in magnitude and opposite in direction to the weight of the object. Therefore, the work done by the drag force is equal to the negative of the work done by gravity, which is given by the formula: Work = -mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the difference in height.

Substituting the given values, we can calculate the work done by gravity as follows:

Work = -0.150 kg x 9.8 m/s^2 x (13.00 m - 6.70 m)

Work = -0.150 kg x 9.8 m/s^2 x 6.30 m

Work = -0.150 kg x 61.74 J

Therefore, the work done by the drag force on the object is 61.74 J (in Joules).

User Design By Adrian
by
8.2k points