Question

Given that f(x) = 3x + 1 and g(x)

(4x + 2)/3, solve for g(f(0)).

1) 2

2) 6

3) 8

4) 9

Answer 1

g(f(0)). =g(3×0+1)=g(1)=(4×1+2)/3=6/3=2