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In the book, it is written that from 0 s to 0.125 s-Atrial Systole; 0.125 s to 0.325 s-Ventricular Systole; 0.325 s to 0.6 s-Ventricular Diastole

Why a bump is there from 0.125 s to about 0.175 s in the pressure-time graph of left atrial pressure and why is the pressure in the left auricle increasing during the ventricular systole and ventricular diastole stage (from 0.175 s to 0.45 s)?

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Final answer:

The bump in the left atrial pressure graph corresponds to the ventricular systole phase, where the closed atrioventricular valves cause a slight increase in atrial pressure. Atrial pressure continues to rise during diastole as the atria fill with blood from the pulmonary veins. Together, systole and diastole compose the cardiac cycle which includes the coordination of the heart's contractions and relaxations.

Step-by-step explanation:

The bump observed in the pressure-time graph of left atrial pressure from 0.125 s to about 0.175 s corresponds to the ventricular systole phase of the cardiac cycle. During this phase, the atrioventricular valves are closed, and the contraction of the ventricles generates high pressure, pushing a small amount of blood back into the atria, causing a slight increase in atrial pressure. This is reflected as a bump on the graph.

Additionally, the pressure in the left atrium continues to increase during the ventricular systole and ventricular diastole stage (from 0.175 s to 0.45 s) due to the accumulation of blood from the pulmonary veins. This is because, during the ventricular systole, the atria are relaxed and filling with blood, and during the early part of ventricular diastole, the atrioventricular valves remain closed, allowing atrial pressure to rise as they fill further until these valves open, and blood flows into the relaxed ventricles.

The period from the onset of atrial contraction to the end of ventricular relaxation is termed the cardiac cycle, which includes phases of both systole (contraction) and diastole (relaxation) necessary for efficient blood pumping.

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