The probability of selecting a girl first and a boy second from a group of 12 girls and 3 boys is 0.2286 or 22.86%.
To find the probability, we need to calculate the number of favorable outcomes and the total number of possible outcomes.
There are 12 girls and 3 boys in the group, so the total number of children is 15.
For the first child selected, there are 15 options. For the second child, there are 14 options from the remaining children.
Therefore, the probability of selecting a girl first and a boy second is:
(12/15) x (3/14) = 0.2286 or 22.86%
The probable question may be:
There are 12 girls and 3 boys in a group of children. One child was chosen at random from the group. Another child was chosen at random from the remaining children. What is the probability that selecting a girl first and a boy second?