Question

The charge of an electron is -1.6*10^-19 C. Silver has an atomic number of 47. There are approximately 1.6*10^23 silver atoms in a 1 ounce silver coin. What is the net charge of all of the electrons in 1 such coin? PLEASE ANSWER ASAP!!

Answer 1

The net charge of all electrons in a 1 ounce silver coin is calculated by multiplying the total number of electrons in the coin by the charge of one electron, resulting in approximately -1.2032 x 10^6 coulombs.

Step-by-step explanation:

To find the net charge of all the electrons in a 1 ounce silver coin, we first need to consider that silver has an atomic number of 47, meaning each silver atom has 47 electrons.

With approximately 1.6 x 1023 silver atoms in the coin, the total number of electrons is 47 electrons/atom x 1.6 x 1023 atoms.

The charge of a single electron is -1.6 x 10-19 coulombs (C).

Thus, to calculate the net charge, we multiply the number of electrons by the charge per electron:

1. Calculate the total number of electrons in the coin: 47 x 1.6 x 1023 = 7.52 x 1024 electrons.
2. Multiply this by the charge of one electron: 7.52 x 1024 electrons x (-1.6 x 10-19 C/electron) = -1.2032 x 106 C.

The net charge of all electrons in a 1 ounce silver coin is approximately -1.2032 x 106 coulombs.