56.9k views
1 vote
Perpendicular to the line y = -2x - 7 passes through (-3,10)

User Jiya
by
8.0k points

1 Answer

3 votes

Final answer:

To find a line perpendicular to the given line y = -2x - 7, we need to find the negative reciprocal of the slope of the given line. We can then use the point-slope form of a linear equation to find the equation of the perpendicular line through the given point (-3, 10).

Step-by-step explanation:

To find a line perpendicular to a given line, we need to find the negative reciprocal of the slope of the given line. In this case, the given line has a slope of -2.

The negative reciprocal of -2 is 1/2. So, the line perpendicular to y = -2x - 7 will have a slope of 1/2.

Next, we can use the point-slope form of a linear equation to find the equation of the perpendicular line.

The point-slope form is given by y - y1 = m(x - x1) where (x1, y1) is a point on the line and m is the slope.

Substituting the given point (-3, 10) and the slope 1/2 into the point-slope form, we get y - 10 = 1/2(x - (-3)).

Simplifying the equation, we get y - 10 = 1/2(x + 3).

This is the equation of the line perpendicular to y = -2x - 7 that passes through (-3, 10).

User Oberbaum
by
7.5k points