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If we consider a reaction A+B⟶3C The rate of reaction is given by R=−Δ[A]Δt=−Δ[B] Δt=13Δ[C]Δt [C]Δt I know we divide it by3 for equality, but we can also multiply33in other two concentrations too, right? Then the result will be: R=−3Δ[A] Δt=−3Δ[B] Δt=Δ[C] ΔtR=−3Δ[A] Δt=−3Δ[B] Δt=Δ[C]Δt So is it just a convention to divide instead of multiplication?

User Abdo
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Final answer:

The rate of reaction in a chemical equation is determined by the change in concentration of the reactants or products. In this specific reaction, for every 1 mole of reactant A or B consumed, 1/3 mole of product C is produced. The convention to divide instead of multiply by 3 is based on the stoichiometry of the reaction.

Step-by-step explanation:

The rate of reaction in a chemical equation is given by the change in concentration of the reactants or products over a period of time. In the equation A + B ⟶ 3C, the rate of reaction can be expressed as R = −Δ[A]/Δt = −Δ[B]/Δt = 1/3 Δ[C]/Δt. This means that for every 1 mole of A or B consumed, 1/3 mole of C is produced. The convention to divide instead of multiply by 3 is based on the stoichiometry of the reaction, where the coefficients of A and B in the balanced equation are 1, and the coefficient of C is 3.

User Debu Shinobi
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