Question

"From what I understand, the solubility is given in terms of molar solubility (orKspKsp), from which it can be easily calculated). Indeed, the saturation point represents the maximum amount of a slightly soluble substance in an aqueous solution that solubilizes (dissociates).

Therefore, in extremely small amounts even very sparingly soluble salts with extremely small molar solubilities (andK′sp) can be completely ionized. For instance,HgSis one of the least soluble inorganic substances with a molar solubility of about10X−27. Now, if I put up to10X−27moles of HgS in 1L of water, will it be completely dissolved intoHgX₂+andSX₂?

Answer 1

Molar solubility relates to the maximum solubility of a compound in solution, determined by the solubility product constant (Ksp). Mercury sulfide (HgS) will ionize into Hg2+ and S2- up to its molar solubility, which shows the extent to which it can dissolve and ionize in water.

Step-by-step explanation:

The question concerns the concept of molar solubility and its relationship to the solubility product constant (Ksp) in the context of sparingly soluble salts like HgS (mercury sulfide). When a tiny amount up to its molar solubility is added to water, will it fully ionize into its constituent ions?

The solubility product constant Ksp is a measure of the extent of solubility of a slightly soluble electrolyte. It is calculated from the solubility of the compound and vice versa, assuming that the formation of ions is the only significant reaction when the substance dissolves.

In the case of HgS in water, if you add up to its calculated molar solubility (10^-27 moles per liter), the solution is expected to be at equilibrium and fully saturated. Each molecule of HgS would dissociate to form Hg^2+ and S^2- ions. It is important to note, though, that the solution's actual behavior may be influenced by factors such as pH and presence of complexing agents or other salts.