Question

The maximum wavelengthλλcapable of breaking a chemical bond can be estimated asλ=hc/E.λ=hc/E.UV-A(380nm)(380nm)can break bonds with the energy up to315kJmol−1,315kJmol−1,UV-B(320nm)(320nm)can break374kJmol−1374kJmol−1bonds, etc. So, the sunlight (at UV) can break both theC−CC−Cand theC−OC−Obonds. Sunlight has enough energy to break up vitamin C molecules in juice. Supposedly plants have some excision repair. But on the chemistry side, when UV breaks a bond, what's the probability the bond can just reform back?

Answer 1

The probability of a bond reforming after being broken by UV light depends on various factors such as the nature and strength of the bond, conditions, and presence of reactants or catalysts. Bonds can potentially reform through a reaction involving the rearrangement of atoms or molecules, but it is not always guaranteed. Some bonds may undergo irreversible reactions.

Step-by-step explanation:

The probability that a bond can reform after being broken by UV light depends on various factors such as the nature and strength of the bond, the conditions in the system, and the presence of any reactants or catalysts that can facilitate the reforming of the bond. In general, if the conditions are favorable, bonds can reform through a process called a reaction. This involves the rearrangement of atoms or molecules to create new bonds.

However, the reforming of a bond after it has been broken by UV light is not always guaranteed. Some bonds may undergo irreversible reactions, leading to the formation of new products or the degradation of molecules. It is important to note that the probability of bond reforming can vary depending on the specific bond and the circumstances.